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NEW QUESTION # 30
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID - must be able to contain a maximum of 12 alphanumeric characters and uniquely identify the row
EXECUTION_DATETIME - contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently?
- A. The COMPONENT_ID must be of ROWID data type.
- B. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.
- C. The EXECUTION_DATATIME must be of DATE data type.
- D. The COMPONENT_ID must be of VARCHAR2 data type.
- E. The EXECUTION _DATETIME must be of TIMESTAMP data type.
- F. The COMPONENT_ID column must be of CHAR data type.
Answer: C,D
NEW QUESTION # 31
Evaluate the following ALTER TABLEstatement:
ALTER TABLE orders
SET UNUSED (order_date);
Which statement is true?
- A. After executing the ALTER TABLEcommand, you can add a new column called ORDER_DATEto the ORDERStable.
- B. ROLLBACKcan be used to get back the ORDER_DATEcolumn in the ORDERStable.
- C. The DESCRIBEcommand would still display the ORDER_DATEcolumn.
- D. The ORDER_DATEcolumn should be empty for the ALTER TABLEcommand to execute successfully.
Answer: A
NEW QUESTION # 32
View the exhibit and examine the description of the PRODUCT_INFORMATIONtable.
Which SQL statement would retrieve from the table the number of products having LIST_PRICEas NULL?
SELECT COUNT (DISTINCT list_price)
- A. FROM product_information
WHERE list_price i= NULL
SELECT COUNT (list_price) - B. FROM product_information
WHERE list_price is NULL
SELECT COUNT (list_price) - C. FROM product_information
WHERE list_price is NULL - D. FROM product_information
WHERE list_price is NULL
SELECT COUNT (NVL(list_price, 0))
Answer: B
NEW QUESTION # 33
Which three statements are true regarding group functions? (Choose three.)
- A. They can be passed as an argument to another group function.
- B. They can be used on columns or expressions.
- C. They can be used only with a SQL statement that has the GROUP BY clause.
- D. They can be used along with the single-row function in the SELECT clause of a SQL statement.
- E. They can be used on only one column in the SELECT clause of a SQL statement.
Answer: A,B,D
Explanation:
References:
https://www.safaribooksonline.com/library/view/mastering-oracle-
sql/0596006322/ch04.html
NEW QUESTION # 34
View the exhibit and examine the data in ORDERS_MASTERand MONTHLY_ORDERStables.
Evaluate the following MERGEstatement:
MERGE_INTO orders_master o
USING monthly_orders m
ON (o.order_id = m.order_id)
WHEN MATCHED THEN
UPDATE SET o.order_total = m.order_total
DELETE WHERE (m.order_total IS NULL)
WHEN NOT MATCHED THEN
INSERT VALUES (m.order_id, m.order_total)
What would be the outcome of the above statement?
- A. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2, 3 and 4.
- B. The ORDERS_MASTERtable would contain the ORDER_IDs1 and 2.
- C. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2 and 4.
- D. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2 and 3.
Answer: C
Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_9016.htm
NEW QUESTION # 35
Evaluate the following statement.
Which statement is true regarding the evaluation of rows returned by the subquery in the INSERT statement?
- A. They are evaluated by all the three WHEN clauses regardless of the results of the evaluation of any other WHEN clause.
- B. The insert statement would give an error because the ELSE clause is not present for support in case none of WHEN clauses are true.
- C. They are evaluated by the first WHEN clause. If the condition is true, then the row would be evaluated by the subsequent WHEN clauses.
- D. They are evaluated by the first WHEN clause. If the condition is false, then the row would be evaluated by the subsequent WHEN clauses.
Answer: A
Explanation:
Explanation
http://psoug.org/definition/WHEN.htm
NEW QUESTION # 36
Evaluate the following query
What is the correct output of the above query?
- A. +00-300, +00-650, +00 11:12:10.123457
- B. +25-00, +54-02, +00 11:12:10.123457
- C. +25-00, +00-650, +00 11:12:10.123457
- D. +00-300, +54-02, +00 11:12:10.123457
Answer: B
NEW QUESTION # 37
Examine this SELECT statement and view the Exhibit to see its output:
SELECT constraints_name, constraints_type, search_condition, r_constraint_name, delete_rule, status,
FROM user_constraints
WHERE table_name = 'ORDERS';
Which two statements are true about the output? (Choose two.)
- A. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
- B. The STATUS column indicates whether the table is currently in use.
- C. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
- D. In the second column, 'c' indicates a check constraint.
Answer: A,D
NEW QUESTION # 38
View the exhibit for the structure of the STUDENTand FACULTYtables.
STUDENT
Name Null? Type
------------------ ------------------- -------------
STUDENT_ID NOT NULL NUMBER(2)
STUDENT_NAME VARCHAR2(20)
FACULTY_ID VARCHAR2(2)
LOCATION_ID NUMBER(2)
FACULTY
Name Null? Type
- ----------------- ------------------- -------------
FACULTY_ID NOT NULL NUMBER(2)
FACULTY_NAME VARCHAR2(20)
LOCATION_ID NUMBER(2)
You need to display the faculty name followed by the number of students handled by the faculty at the base location.
Examine the following two SQL statements:
Statement 1
SQL>SELECT faculty_name, COUNT(student_id)
FROM student JOIN faculty
USING (faculty_id, location_id)
GROUP BY faculty_name;
Statement 2
SQL>SELECT faculty_name, COUNT(student_id)
FROM student NATURAL JOIN faculty
GROUP BY faculty_name;
Which statement is true regarding the outcome?
- A. Both statements 1 and 2 execute successfully and give different results.
- B. Only statement 2 executes successfully and gives the required result.
- C. Only statement 1 executes successfully and gives the required result.
- D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: C
NEW QUESTION # 39
View the Exhibit and examine the structure of the CUSTOMERStable.
CUSTOMER_VUis a view based on CUSTOMERS_BR1 table which has the same structure as CUSTOMERStable.
CUSTOMERSneed to be updated to reflect the latest information about the customers.
What is the error in the following MERGEstatement?
- A. The WHEREclause cannot be used with INSERT.
- B. The CUSTOMER_IDcolumn cannot be updated.
- C. The INTOclause is misplaced in the command.
- D. CUSTOMER_VUcannot be used as a data source.
Answer: B
NEW QUESTION # 40
Which two are true about the precedence of opertors and condtions
- A. AND and OR have the same order of precedence in a condition
- B. NOT has a higher order of precedence than AND and OR in a condition.
- C. + (addition) has a higher order of precedence than * (mliplpition)
- D. Operators are evaluated before conditions.
- E. || has a higher order of precedence than +(addition)
Answer: B,D
NEW QUESTION # 41
Examine the data in the COLORS table:
Examine the data in the BRICKS table:
Which two queries return all the rows from COLORS?
- A. SELECT.
FROM bricks b
RIGHT JOIN colors c
ON b. color _rgb_ hex_ value = c. rgb hex_ value; - B. SELECT
FROM bricks b
FULL JOIN colors C
ON b. color rgb _ hex_ value = c. rgb _hex_ value; - C. SELECT *
EROM bricks | b
JOIN colors C
ON b. color_ rgb_ hex_ value =c. rgb _hex value; - D. SELECT
EROM colors C
LEET JOIN bricks b
ON b. color_ rgb_ hex value = c. rgb. hex.
value
WHERE b. brick_ id > 0; - E. SELECT
EROM colors C
LEFT JOIN bricks b
USING (rgb _ hex_ value) ;
Answer: A,B
NEW QUESTION # 42
Which two statements are true regarding the COUNT function? (Choose two.)
- A. The COUNT function can be used only for CHAR, VARCHAR2 and NUMBER data types
- B. COUNT(*) returns the number of rows including duplicate rows and rows containing NULL value in any of the columns
- C. COUNT(cust_id) returns the number of rows including rows with duplicate customer IDs and NULL value in the CUST_ID column
- D. COUNT(DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULL values in the INV_AMT column
- E. A SELECT statement using COUNT function with a DISTINCT keyword cannot have a WHERE clause
Answer: B,D
NEW QUESTION # 43
On your Oracle 12c database, you invoked SQL *Loader to load data into the EMPLOYEES table in the HR schema by issuing the following command:
$> sqlldr hr/hr@pdb table=employees
Which two statements are true regarding the command?
- A. It fails if the HR user does not have the CREATE ANY DIRECTORY privilege.
- B. It fails because no SQL *Loader data file location is specified.
- C. It fails because no SQL *Loader control file location is specified.
- D. It succeeds with default settings if the EMPLOYEES table belonging to HR is already defined in the database.
Answer: A,D
NEW QUESTION # 44
Evaluate the following CREATE TABLEcommand:
Which statement is true regarding the above SQL statement?
- A. It would execute successfully and two indexes ORD_ITM_IDX and ORD_ITM_ID_PK would be created.
- B. It would give an error because the USING INDEX clause cannot be used on a composite primary.
- C. It would execute successfully and only ORD_ITM_IDX index would be created.
- D. It would give an error because the USING INDEX clause is not permitted in the CREATE TABLE command.
Answer: C
NEW QUESTION # 45
Examine this query:
SELECT INTERVAL '100' MONTH DURATION FROM DUAL;
What will be the output?
- A. DURATION
+08-04 - B. DURATION
+08 - C. DUFATION
+100 - D. an error
Answer: A
NEW QUESTION # 46
View the exhibit and examine the description of the DEPARTMENTS and EMPLOYEES tables.
The retrieve data for all the employees for their EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, the following SQL statement was written:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?
- A. The EMPLOYEES and DEPARTMENTS tables have more than one column with the same column name and data type.
- B. The DEPARTMENTS table is not used before the EMPLOYEES table in the FROM clause.
- C. The NATURAL JOIN clause is missing the USING clause.
- D. The table prefix is missing for the column names in the SELECT clause.
Answer: A
Explanation:
Explanation
Natural join needs only one column to be the same in each table. The EMPLOYEES and DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID)
NEW QUESTION # 47
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